Timed problem B: the double-issued ticket
Why it matters This is the matched twin of timed problem A, timed the same way. The tutor is switched off: work it out yourself.
A ticketing system hands out numbers one after another. After a failover, two machines briefly issued the same number, so in tonight's export exactly one number appears twice. The export is sorted. Support wants the repeated number to contact both customers.
The export sits on the same charged-per-read storage as the invoice archive, so each check gets a small read budget.
The data
from creative.budget import Tape
tape = Tape([300, 301, 302, 302, 303, 304])
# duplicate_ticket(tape) -> 302Write duplicate_ticket(tape). tape is a Tape of sorted whole numbers that run one after another from the first to the last, except that exactly one number appears twice (it may be the first or the last). Return that number. Budget: on a run of about 100,000 tickets you may read at most 100 values. len(tape) is free.
AI off: no tutor, hints or worked solution on this one. Your own thinking only.
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